Projectile Motion: Example Part 2
About the Lecture
The lecture Projectile Motion: Example Part 2 by Jared Rovny, PhD is from the course Translational Motion.
Included Quiz Questions
A projectile launches with an initial speed of V at an angle of θ with the horizontal. What is the formula for its maximum height?
- V²sin²θ/(2g)
- V²sin²θ/g
- Vsin²θ/(2g)
- V²/(2g)
- Vsinθ/(2g)
A firefighter aims a water hose upward at an angle of 78.5° with the horizontal and an initial speed of 32 m/s. What is the maximum height of the water stream? (g ≈ 10 m/s²)
- 49 m
- 5.0 m
- 1000 m
- 55 m
- 502 m
An athlete in a high jump competition leaves the ground at an angle of 87° and attains the maximum height of 1.7 m. What is the initial speed of the athlete at the time of jump? Hint: Use the maximum height formula.
- 5.8 m/s
- 58 m/s
- 33 m/s
- 3.4 m/s
- 5 m/s
A projectile launches with an initial speed of V at an angle of θ with the horizontal. What is its vertical velocity at its highest point of motion?
- Zero
- Vsinθ
- -Vsinθ
- V
- Vcosθ
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Author of lecture Projectile Motion: Example Part 2
Jared Rovny, PhD
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